x^2=3+2.5x

Solution for x^2=3+2.5x equation:

x^2=3+2.5x

We move all terms to the left:

x^2-(3+2.5x)=0

We add all the numbers together, and all the variables

x^2-(2.5x+3)=0

We get rid of parentheses

x^2-2.5x-3=0

a = 1; b = -2.5; c = -3;
Δ = b2-4ac
Δ = -2.52-4·1·(-3)
Δ = 18.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.5)-\sqrt{18.25}}{2*1}=\frac{2.5-\sqrt{18.25}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.5)+\sqrt{18.25}}{2*1}=\frac{2.5+\sqrt{18.25}}{2}
$